Tìm x,y a) $\frac{x}{10}$ = $\frac{-7}{-y}$ = $\frac{-4}{8}$ (x,y ∈ z) (y ∉ 0) b)|-2x+ $\frac{1}{-3}$ |= $\frac{8}{6}$

Question

Tìm x,y
a) $\frac{x}{10}$ = $\frac{-7}{-y}$ = $\frac{-4}{8}$
(x,y ∈ z) (y ∉ 0)
b)|-2x+ $\frac{1}{-3}$ |= $\frac{8}{6}$

in progress 0
Xavia 5 years 2021-04-29T01:28:35+00:00 2 Answers 32 views 0

Answers ( )

  1. RuslanHeatt
    0
    2021-04-29T01:30:15+00:00
    Reply

    Gửi ạ

    tim-y-a-frac-10-frac-7-y-frac-4-8-y-z-y-0-b-2-frac-1-3-frac-8-6

  2. Ladonna
    0
    2021-04-29T01:30:26+00:00
    Reply

    Đáp án + Giải thích các bước giải:

    a)

    `x/10=(-7)/(-y)=(-4)/8`

    `to x/10=7/y=-1/2`

    `+) \ x/10=-1/2 to 2x=-10 to x=-5`

    `+) \ 7/y=-1/2 to y=-14`

    Vậy `(x;y)=(-5;-14)`

    b)

    `|-2x+1/(-3)|=8/6=4/3`

    `to` \(\left[ \begin{array}{l}-2x+\dfrac{1}{-3}=\dfrac{4}{3} \\ -2x+\dfrac{1}{-3}=-\dfrac{4}{3}\end{array} \right.\)`to`\(\left[ \begin{array}{l}-2x=\dfrac{4}{3}-\dfrac{1}{-3}\\-2x=-\dfrac{4}{3}-\dfrac{1}{-3}\end{array} \right.\)

    `to`\(\left[ \begin{array}{l}-2x=\dfrac{5}{3}\\-2x=-1\end{array} \right.\)`to` \(\left[ \begin{array}{l}x=-\dfrac{5}{6}\\x=\dfrac{1}{2}\end{array} \right.\)

    Vậy `x in {-5/6;1/2}`

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )