Tìm x (34.2x).(2x-6) = 0 (2019-x).(3x-12) = 0 57.(9x-27) = 0 3.(x+7)-15 = 27 25+3.(5-x) = 27

Question

Tìm x
(34.2x).(2x-6) = 0
(2019-x).(3x-12) = 0
57.(9x-27) = 0
3.(x+7)-15 = 27
25+3.(5-x) = 27

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Ben Gia 6 years 2020-11-28T02:54:35+00:00 2 Answers 114 views 0

Answers ( )

  1. minhkhang
    0
    2020-11-28T02:55:40+00:00
    Reply

    Lời giải chi tiết:

    `a,(34*2x)(2x-6)=0`

    `<=>34*2x=0` hoặc `2x-6=0`

    `<=>x=0` hoặc `x=3`

    `b,(2019-x)(3x-12)=0`

    `<=>x=2019` hoặc `x=4`

    `c,57(9x-27)=0`

    `<=>9x-27=0`

    `<=>9x=27`

    `<=>x=3` 

    `d,3(x+7)-15=27`

    `<=>3(x+7)=42`

    `<=>x+7=14`

    `<=>x=7`

    `e,25+3(5-x)=27`

    `<=>3(5-x)=2`

    `<=>5-x=2/3`

    `<=>x=2/15`

    Vậy ……………………

  2. Calantha
    0
    2020-11-28T02:56:15+00:00
    Reply

    `a,(34*2x)(2x-6)=0`

    `<=>34*2x=0` hoặc `2x-6=0`

    `<=>x=0` hoặc `x=3`

    Vậy ….

    `b,(2019-x)(3x-12)=0`

    `<=>x=2019` hoặc `x=4`

    Vậy …..

    `c,57(9x-27)=0`

    `<=>9x-27=0`

    `<=>x=3`

    Vậy …. 

    `d,3(x+7)-15=27`

    `<=>3(x+7)=42`

    `<=>x+7=14`

    `<=>x=7`

    Vậy …….

    `e,25+3(5-x)=27`

    `<=>3(5-x)=2`

    `<=>5-x=2/3`

    `<=>x=2/15`

     Vậy ….

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