Three identical capacitors are connected in series across a potential source (battery). If a charge of Q flows into this combination of capa

Question

Three identical capacitors are connected in series across a potential source (battery). If a charge of Q flows into this combination of capacitors, how much charge does each capacitor carry?

a.Q
b.3Q
c.Q/9
d.Q/3

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Kiệt Gia 3 years 2021-09-05T13:09:09+00:00 1 Answers 23 views 0

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  1. Euphemia
    0
    2021-09-05T13:10:31+00:00
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    Answer:

    a) Q

    Explanation:

    • If the capacitors are connected in series, across a potential source (battery) , the battery voltage is divided between the capacitors, as follows:

           V = V_{1} + V_{2} +V_{3}

    • By definition, each voltage is related with the capacitance and the charge, as follows:

            V = V_{1} + V_{2} +V_{3} = \frac{Q_{1} }{C_{1}} + \frac{Q_{2} }{C_{2}} + \frac{Q_{3} }{C_{3}}

    • Now, due to the principle of conservation of charge, this can’t neither accumulate nor dissapear at any point  in the circuit, so the charge must be the same for  each capacitor:

           Q = Q_{1} = Q_{2} = Q_{3}

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