Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another. The cubes are lined up from left t

Question

Three identical 6.0-kg cubes are placed on a horizontal frictionless surface in contact with one another. The cubes are lined up from left to right and a force is applied to the left side of the left cube causing all three cubes to accelerate to the right at 2.0 m/s2. What is the magnitude of the force exerted on the middle cube by the left cube in this case

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RobertKer 5 years 2021-08-28T05:01:23+00:00 1 Answers 9 views 0

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    2021-08-28T05:02:40+00:00

    Answer:

    24 Newtons

    Explanation:

    The force exerted in the middle cube needs to be enough to move the middle cube and the right cube with an acceleration of 2 m/s2.

    The mass of those two cubes combined is 6 + 6 = 12 kg

    So, using the following equation, we can find the force:

    Force = mass * acceleration

    Force = 12 * 2

    Force = 24 Newtons

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