The width of a rectangle is 6n – 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

Question

The width of a rectangle is 6n – 2.5 feet and the length is 2.5 + 8 feet. Find the perimeter of the rectangle.

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Kim Cúc 5 years 2021-08-29T17:49:25+00:00 1 Answers 11 views 0

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  1. danthu
    0
    2021-08-29T17:51:10+00:00
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    I was thinking the measurement for ;length should be 2.5n + 8 feet since width is 6n -2.5 feet , but you gave 2.5+ 8 feet, so i will solve it in both ways

    Answer:  Perimeter =  5 + 12n + 11 feet ; Perimeter =  17n+ 11 feet

    Step-by-step explanation:

    Using Length = 2.5+ 8 feet,

    Perimeter of  a rectangle is calculated as 2( l+ b)

    Given that width=6n – 2.5 feet

    length =2.5 + 8 feet

    Perimeter =2( l+ b)= 2L + 2B

    Perimeter= 2(2.5 + 8feet ) + 2( 6n – 2.5 feet)

    Perimeter = 5 + 16feet + 12n – 5feet

    Perimeter =  5 + 12n + 11 feet

    Using Length = 2.5n+ 8 feet,

    Perimeter of  a rectangle is calculated as 2( l+ b)

    Given that width=6n – 2.5 feet

    length =2.5n+ 8 feet

    Perimeter =2( l+ b)= 2L + 2B

    Perimeter= 2(2.5n + 8feet ) + 2( 6n – 2.5 feet)

    Perimeter = 5n + 16feet + 12n – 5feet

    Perimeter =  5n + 12n + 11 feet

    Perimeter =  17n+ 11 feet

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