The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a pendulum (t

Question

The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a pendulum (to nearest hundredth) if it makes one swing in 2.1 seconds? Use 3.14 for \pi .

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Ladonna 3 years 2021-08-14T04:12:00+00:00 1 Answers 31 views 0

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  1. Orla
    0
    2021-08-14T04:13:43+00:00
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    Answer:

    3.6ft

    Explanation:

    Using= 2*π*sqrt(L/32)

    To solve for L, first move 2*n over:

    T/(2*π) = sqrt(L/32)

    Next,eliminate the square root by squaring both sides

    (T/(2*π))2 = L/32

    or

    T2/(4π2) = L/32

    Lastly, multiply both sides by 32 to yield:

    32T2/(4π2) = L

    and simplify:

    8T²/π²= L

    Hence, L(T) = 8T²/π²

    But T = 2.1

    Pi= 3.14

    8(2.1)²/3.14²

    35.28/9.85

    = 3.6feet

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