The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4 → 10x − 5y = −20 3x + 5y = 59

Question

The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4 → 10x − 5y = −20 3x + 5y = 59 → 3x + 5y = 59 13x = 39 Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

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Bình An 3 years 2021-08-29T12:38:46+00:00 1 Answers 4 views 0

Answers ( )

  1. Helga
    0
    2021-08-29T12:40:32+00:00
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    Answer:

    13x=39

    Step-by-step explanation:

    Given

    2x - y = -4 \to 10x - 5y =-20

    3x +5y =59 \to 3x +5y = 59

    Required

    What can replace 3x +5y = 59 ?

    We have:

    10x - 5y =-20

    and

    3x +5y = 59

    Add up both equations:

    10x +3x-5y+5y=-20+59

    10x +3x=39

    13x=39

    Since 13x=39 is a result of 10x - 5y =-20 and 3x +5y = 59,

    13x=39 can replace 10x +3x=39

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )