The sum of Ivy’s and Audrey’s ages is 27. Nine years ago, Ivy was twice as old as Audrey. How old is each now?

Question

The sum of Ivy’s and Audrey’s ages is 27. Nine years ago, Ivy was
twice as old as Audrey. How old is each now?

in progress 0
Farah 4 years 2021-07-19T04:09:38+00:00 1 Answers 22 views 0

Answers ( )

  1. Doris
    0
    2021-07-19T04:11:24+00:00
    Reply

    Answer:

    Ivy is 15 years old and Audrey is 12 years old.

    Step-by-step explanation:

    Let Ivy’s age be i and Audrey’s age be a.

    Since the sum of their ages is 27, we can write the equation i+a=27.

    Next, we’ll write a second equation from the fact that 9 years ago Ivy was twice as old as Audrey. Nine years ago, Ivy and Audrey’s ages were i-9 and a-9, respectively. Therefore, we have i-9=2(a-9)

    Let’s isolate i by adding 9 to both sides:

    i=2(a-9)+9

    Distribute:

    i=2a-18+9,\\i=2a-9

    Now substitute i=2a-9 into our first equation:

    2a-9+a=27,\\3a-9=27, \\3a=36, \\a=\boxed{12}

    Therefore, Ivy’s age must be:

    i+12=27,\\i=27-12=\boxed{15}

    Thus, Ivy must be 15 years old and Audrey must be 12 years old.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )