The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers. <

Question

The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers.

A.
n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27

B.
n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27

C.
n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14

D.
n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15

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Neala 5 years 2021-09-02T04:14:20+00:00 1 Answers 27 views 0

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  1. thongdat2
    0
    2021-09-02T04:16:16+00:00
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    Answer:

    D. n+n+2+n+4+6= -72; n= -21; n+2= -19; n+4= -17; n+6= -15

    There are 2 below and 2 above it.

    -15, -17, -19, -21

    Step-by-step explanation:

    the sum of four consecutive odd integers is -72. write an equation to model this situation, and find the values of the four integers
    .

    n + n+2 + n+4 + n+6 = -72

    4n + 12 = -72

    or

    -72/4 = -18, the center

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