The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver’s seat. Part A If the car goes over a bump, wh

Question

The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver’s seat. Part A If the car goes over a bump, what will be the frequency of oscillations

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Trung Dũng 5 years 2021-07-30T18:11:53+00:00 1 Answers 334 views 0

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  1. quangkhai
    0
    2021-07-30T18:13:10+00:00
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    Answer:

    the frequency of the oscillation is 1.5 Hz

    Explanation:

    Given;

    mass of the spring, m = 1500 kg

    extention of the spring, x = 5 mm = 5 x 10⁻³ m

    mass of the driver = 68 kg

    The weight of the driver is calculated as;

    F = mg

    F = 68 x 9.8 = 666.4 N

    The spring constant, k, is calculated as;

    k = F/m

    k = (666.4 N) / (5 x 10⁻³ m)

    k = 133,280 N/m

    The angular speed of the spring is calculated;

    \omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s

    The frequency of the oscillation is calculated as;

    ω = 2πf

    f = ω / 2π

    f = (9.426) / (2π)

    f = 1.5 Hz

    Therefore, the frequency of the oscillation is 1.5 Hz

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