The shuttles main engine provides 154,360 kg of thrust for 8 minutes. If the shuttle accelerated at 29m/s/s, and fires for at least 8 minute

Question

The shuttles main engine provides 154,360 kg of thrust for 8 minutes. If the shuttle accelerated at 29m/s/s, and fires for at least 8 minutes, then how far does the shuttle go

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Khoii Minh 5 years 2021-09-04T19:47:45+00:00 1 Answers 16 views 0

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  1. Eirian
    0
    2021-09-04T19:49:21+00:00
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    Answer:

    The answer to the question is

    3340800 m far

    Explanation:

    To solve the question, we note that acceleration = 29 m/s²

    Time of acceleration = 8 minutes

    Then if the shuttle starts from rest, we have

    S = u·t+0.5·a·t² where u = 0 m/s = initial velocity

    S = distance traveled, m

    a = acceleration of the motion, m/s²

    t = time of travel

    S = 0.5·a·t² = 0.5×29×(8×60)² = 3340800 m far

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