The root for an equation x²-px+6=0 ls 3. Find the value of p Jawapan / Anne IP​

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The root for an equation x²-px+6=0 ls 3. Find the value of p
Jawapan / Anne
IP​

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RuslanHeatt 5 years 2021-09-01T11:08:19+00:00 1 Answers 10 views 0

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    2021-09-01T11:10:02+00:00
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    Answer:

    5

    Step-by-step explanation:

    Given that 3 is a root of the equation x²-px+6=0

    To find the value of p, substitute 3 into the equation for x

    Hence x²-px+6=0

    becomes

    3^2 – 3p + 6 = 0

    9 -3p + 6 = 0

    collect like terms

    -3p = -9 – 6

    -3p = -15

    Divide both sides by -3

    p = -15/-3

    p = 5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )