The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was

Question

The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argon sample was 14.2 L what what’s the initial volume of the argon sample? Assume ideal behavior

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Thu Nguyệt 5 years 2021-08-31T01:42:11+00:00 1 Answers 21 views 0

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    0
    2021-08-31T01:44:03+00:00

    Answer:

    36.09 L

    Explanation:

    The initial volume can be found by using the formula for Boyle’s law which is

    P_1V_1 = P_2V_2

    where

    P1 is the initial pressure

    P2 is the final pressure

    V1 is the initial volume

    V2 is the final volume.

    Since we’re finding the initial volume

    V_1 =  \frac{P_2V_2}{P_1}  \\

    We have

    V_1 =  \frac{7.98 \times 14.2}{3.14} =   \frac{113.316}{3.14}  \\  = 36.0878...

    We have the final answer as

    36.09 L

    Hope this helps you

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