The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

Question

The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

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Latifah 3 weeks 2021-08-23T23:05:30+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-23T23:07:25+00:00

    question:-

    The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

    Answer:-

    • width = 1.88
    • length = 91.88

    let’s find out

    let X = width

    X+90 = length

    so,

    • 2x + 2(x+90) = 340
    • 2x + 2x + 180 = 340
    • 4x + 180 = 340
    • X = 340÷180
    • X = 1.88

    therefore X = 1.88

    so,

    • width = 1.88
    • length = 1.88 + 90 = 91.88

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    related question with solution:

    question:

    The perimeter of a rectangular field is 360 yd. The length is 40 yd longer than the width. Find the dimensions.

    AnsWer

    Let x = width

    x + 40 = length

    2x + 2(x+40) = 360

    4x + 80 = 360

    4x = 280

    x = 70

    Width = x = 70 yd

    Length = x + 40 = 110 yd

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    0
    2021-08-23T23:07:25+00:00

    Answer:

    length= 100 width=70

    Step-by-step explanation:

    The perimeter of a rectangular field is 340 yds.  

    The length is 30 yds longer than the width.  

    2(l + w) = 340

    l + w = 170

    w + 30 + w = 170

    2w = 140

    w = 70

    Hence the dimensions:

    Length: 100 yds.

    Width: 70 yds.

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