## The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

Question

The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

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3 weeks 2021-08-23T23:05:30+00:00 2 Answers 0 views 0

1. question:-

The perimeter of a rectangular field is 340 yards. The length is 90 yd longer than the width. Find the dimensions.

• width = 1.88
• length = 91.88

let’s find out

let X = width

X+90 = length

so,

• 2x + 2(x+90) = 340
• 2x + 2x + 180 = 340
• 4x + 180 = 340
• X = 340÷180
• X = 1.88

therefore X = 1.88

so,

• width = 1.88
• length = 1.88 + 90 = 91.88

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related question with solution:

question:

The perimeter of a rectangular field is 360 yd. The length is 40 yd longer than the width. Find the dimensions.

Let x = width

x + 40 = length

2x + 2(x+40) = 360

4x + 80 = 360

4x = 280

x = 70

Width = x = 70 yd

Length = x + 40 = 110 yd

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length= 100 width=70

Step-by-step explanation:

The perimeter of a rectangular field is 340 yds.

The length is 30 yds longer than the width.

2(l + w) = 340

l + w = 170

w + 30 + w = 170

2w = 140

w = 70

Hence the dimensions:

Length: 100 yds.

Width: 70 yds.