the percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles. If one person

Question

the percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

If one person is selected from each city, what is the probability that all of them are under 18?

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Thanh Thu 4 years 2021-08-05T02:52:34+00:00 1 Answers 7 views 0

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  1. mit
    0
    2021-08-05T02:54:20+00:00
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    Answer:

    0.0158 = 1.58% probability that all of them are under 18.

    Step-by-step explanation:

    Probability of independent events:

    If three events, A, B and C are independent, the probability of all happening is the multiplication of the probabilities of each happening, that is:

    P(A \cap B \cap C) = P(A)P(B)P(C)

    The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.

    This means that P(A) = 0.235, P(B) = 0.258, P(C) = 0.26

    If one person is selected from each city, what is the probability that all of them are under 18?

    Since the three people are independent:

    P(A \cap B \cap C) = 0.235*0.258*0.26 = 0.0158

    0.0158 = 1.58% probability that all of them are under 18.

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