The number of Atoms present in one mole of an element is equal to Avogadro Number. Which One Of the Following contains the greatest number o

Question

The number of Atoms present in one mole of an element is equal to Avogadro Number. Which One Of the Following contains the greatest number of Atoms? (1)4g He (2)46g Na (3)0.40g Ca (4) 12g He​

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Lệ Thu 5 years 2021-07-14T03:20:39+00:00 2 Answers 37 views 0

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  1. Philomena
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    2021-07-14T03:21:46+00:00
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    Answer:

    120gram I think so this is the answer if the answer is correct plz mark me as brainliest.

  2. binhan
    0
    2021-07-14T03:21:46+00:00
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    Answer:

    Thus, the element containing the greatest number of atoms is 12 g He. Thus, the correct option is (4) 12 g He. Note: The number of atoms of a compound is Avogadro’s number for 1 mole of compound. The number 6.022×1023 is known as Avogadro’s number.

    Explanation:

    (4)✔️ 12 g He

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