The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen atom orbits

Question

The nucleus of a hydrogen atom is a single proton, which has a radius of about 1.2 × 10-15 m. The single electron in a hydrogen atom orbits the nucleus at a distance of 5.3 × 10-11 m. What is the ratio of the density of the hydrogen nucleus to the density of the complete hydrogen atom?

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Delwyn 6 months 2021-09-02T21:46:31+00:00 1 Answers 5 views 0

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    2021-09-02T21:48:04+00:00

    Answer: 0.86 × 10^14

    Explanation:

    Given the following :

    Radius of proton = 1.2 × 10-15 m

    Radius of hydrogen atom = 5.3 × 10-11 m

    Density of proton could be calculated thus:

    Mass of proton = 1.67 × 10^-27 kg

    Using the formula :

    (4/3) × pi × r^3

    (4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45

    Density = mass / volume

    Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)

    = 0.2306 × 10^18

    Density of hydrogen atom:

    Mass of hydrogen atom= 1.67 × 10^-27 kg

    Using the formula :

    (4/3) × pi × r^3

    (4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31

    Density = mass / volume

    Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)

    = 0.2676 × 10^4

    Ratio is thus:

    Density of proton / density of hydrogen atom

    0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14

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