The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ????0 . Find the minimum energy nee

Question

The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ????0 . Find the minimum energy needed to eject electrons from a metal with a threshold frequency of 2.47×1014 s−1. g

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Thạch Thảo 6 months 2021-08-23T12:14:01+00:00 1 Answers 0 views 0

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    2021-08-23T12:15:34+00:00

    Answer:

    E = 0.965eV

    Explanation:

    In order to calculate the minimum energy needed to eject the electrons you use the following formula:

    E=h \nu        (1)

    h: Planck’ constant = 6.626*10^{-34}J.s

    v: threshold frequency = 2.47*10^14 s^-1

    You replace the values of v and h in the equation (1):

    E=(6.262*10^{-34}J.s)(2.47*10^{14}s^{-1})=1.54*10^{-19}J

    In electron volts you obtain:

    1.54*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=0.965eV

    The minimum energy needed is 0.965eV

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