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The maximum velocity of a particle executing simple harmonic motion with amplitude 7.0 mm is 4.4 m/s. The period of oscillation is? A. 0.5 s
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Answers ( )
Answer:
D. 0.01 s
Explanation:
The maximum speed is the amplitude times the angular frequency.
v = Aω
4.4 m/s = (0.0070 m) ω
ω = 628.6 rad/s
The period is:
ω = 2π / T
T = 2π / ω
T = 2π / (628.6 rad/s)
T = 0.01 s