The line y = 2x + 6 cuts the x-axis at A and the y-axis at B. Find (a) the length of AB, (b) the shortest distance of O to AB, wh

Question

The line y = 2x + 6 cuts the x-axis at A and the y-axis at B. Find
(a) the length of AB,
(b) the shortest distance of O to AB, where O is the origin (0,0)​

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Thiên Di 5 years 2021-07-31T12:55:50+00:00 1 Answers 49 views 0

Answers ( )

    0
    2021-07-31T12:57:12+00:00

    Answer:

    (a)

    3 \sqrt{5}

    (b)

     \frac{6}{ \sqrt{5} }

    Step-by-step explanation:

    A(-3,0)

    B(0,6)

    d =  \sqrt{{( - 3 - 0)}^{2}   +  {(0 - 6)}^{2} } =  \sqrt{9 + 36}  = 3 \sqrt{5}

    d =  \frac{ax0 + by0 + c}{ \sqrt{ {a}^{2}  +  {b}^{2} } }

    2x-y+6=0

    a=2, b=-1, c=6

    x0=0, y0=0

    d =  \frac{6}{ \sqrt{4 + 1} }  =  \frac{6}{ \sqrt{5} }

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )