The length of a rectangle is 4yd longer than it’s with. If the perimeter of the rectangle is 68yd, find it’s length and width.

Question

The length of a rectangle is 4yd longer than it’s with. If the perimeter of the rectangle is 68yd, find it’s length and width.

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Jezebel 4 years 2021-08-26T08:04:39+00:00 1 Answers 8 views 0

Answers ( )

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    2021-08-26T08:06:19+00:00

    Answer:

    L = 19 yd

    W = 15 yd

    Step-by-step explanation:

    2L + 2W = 68

    L = W + 4

    Substitute for L in the first equation

    2(W + 4) + 2W = 68

    2W + 8 + 2W = 68

    4W = 60

    W = 15 yd

    Plug W in the second equation to find L

    L = W + 4

    L = 15 + 4

    L = 19 yd

    Plug both answers in both equations to check

    First equation = 2 (19) + 2 (15) = 68

    Second equation = 19 = 15 + 4

    Hope that helps!

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