The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of

Question

The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final velocity of the ball before it hits the ground is 33 meters/second. Assuming that the ball experienced a constant acceleration throughout this descent, calculate the magnitude of the acceleration. A. 0.24 g

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Amity 5 months 2021-08-17T07:46:01+00:00 1 Answers 6 views 0

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    2021-08-17T07:47:20+00:00

    Answer:

    Magnitude of the acceleration(g) = 9.7 meters/second²

    Explanation:

    Given:

    Height of tower = 56 meter

    Time taken = 3.4 second

    Final velocity (v) = 33 meters/second

    Initial velocity (u) = 0 meters/second

    Find:

    Magnitude of the acceleration(g)

    Computation:

    Using first equation of motion:

    v = u + at

    Magnitude of the acceleration(g)

    v = u + gt

    33 = 0 + g(3.4)

    g = 33 / 3.4

    g = 9.7 meters/second²

    Magnitude of the acceleration(g) = 9.7 meters/second²

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