the first three ionization energies of an element x are 590, 1145, and 4912 kj mol-1. what is the most likely formula of the compound formed

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the first three ionization energies of an element x are 590, 1145, and 4912 kj mol-1. what is the most likely formula of the compound formed between the stable ion of x and sulfite.

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RuslanHeatt 5 years 2021-07-15T14:25:24+00:00 1 Answers 53 views 0

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    2021-07-15T14:27:10+00:00

    Answer: The chemical formula is XSO_3

    Explanation:

    Ionization energy is defined as the amount of energy that is required to remove an electron from a chemical species.

    The ionization energy equation for the given values follow:

    X(g)\rightarrow X^+(g)+e^-;E_I=590kJ/mol

    X^+(g)\rightarrow X^{2+}(g)+e^-;E_I=1145kJ/mol

    X^{2+}(g)\rightarrow X^{3+}(g)+e^-;E_I=4912kJ/mol

    From the values of ionization energy above, it can be seen that the ionization energy increases as every succeeding electron is removed.

    Second ionization energy is a little higher than the first one but there is a huge amount of difference between the third and second ionization energy.

    This implies that the ion formed during second ionization energy has a stable configuration and it requires a humongous amount of heat to release the third electron.

    Hence, the ion formed will be X^{2+}

    Sulfite ion is a polyatomic ion having a chemical formula of SO_3^{2-}

    An ionic compound is formed between the two ions and the chemical compound formed between the two will have a formula of XSO_3

    Hence, the chemical formula is XSO_3

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