The evil team of Ms. Moonstruck and Mr. Luny intend to deflect the Moon from its orbit around Earth by pulling it with a force of 5910 N . T

Question

The evil team of Ms. Moonstruck and Mr. Luny intend to deflect the Moon from its orbit around Earth by pulling it with a force of 5910 N . They plan to accomplish this by placing a mini black hole 5.09 × 10 6 m from the center of the Moon and letting gravitation do what gravitation does. What must the mass of the mini black hole be for the evil duo’s evil scheme to succeed? The mass of the Moon is 7.36 × 10 22 kg .

in progress 0
Thiên Ân 4 years 2021-07-18T12:41:08+00:00 1 Answers 72 views 0

Answers ( )

  1. yenoanh
    0
    2021-07-18T12:42:34+00:00
    Reply

    Answer:

    The mass of the mini black hole is 31190.28 kg.

    Explanation:

    Given that,

    The Moon from its orbit around Earth by pulling it with a force of 5910 N, F = 5910 N.

    They plan to accomplish this by placing a mini black hole at a distance of 5.09\times 10^6\ m from the center of the Moon.

    Mass of Moon, M=7.36\times 10^{22}\ kg

    We need to find the mass of the mini black hole. There will be gravitational force between moon and the mini black hole. It is given by :

    F=G\dfrac{mM}{r^2}

    m is mass of black hole

    m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{5910\times (5.09\times 10^6)^2}{6.67\times 10^{-11}\times 7.36\times 10^{22}}\\\\m=31190.28\ kg

    So, the mass of the mini black hole is 31190.28 kg.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )