The displacement ‘s’ of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s’ being in cm and ‘t’ in s. The initial velocity

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The displacement ‘s’ of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s’ being in cm and ‘t’ in s. The initial velocity of the particle is:

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Calantha 5 years 2021-07-26T05:59:01+00:00 1 Answers 35 views 0

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  1. Eirian
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    2021-07-26T06:00:19+00:00
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    Answer:

    the initial velocity of the particle is 5 cm/s

    Explanation:

    Given initial displacement as, s = 6t² + 5t – 5

    s is measured in “cm”

    t is measured in “seconds”

    Velocity is the rate of change of displacement with time. Expressed as follows;

    v = \frac{ds}{dt} = 12t + 5

    for initial velocity, time (t) = 0

    v = 12(0) + 5

    v = 5 cm/s

    Therefore, the initial velocity of the particle is 5 cm/s

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