The diffraction phenomenon can be observed whenever the wavelength is comparable in magnitude to the size of the slit opening. To be “diffra

Question

The diffraction phenomenon can be observed whenever the wavelength is comparable in magnitude to the size of the slit opening. To be “diffracted,” how fast must a person weighing 84 kg move through a door 1 m wide

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Acacia 5 months 2021-09-05T06:15:20+00:00 1 Answers 1 views 0

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    2021-09-05T06:16:41+00:00

    Answer:

    Velocity,v=7.89\times10^{-36}m/s

    Explanation:

    Diffraction will only occur when the wavelength,\lambda, is comparable in size to the slit opening. Given the,\lambda=1m,,and mass of the person as 84kg, we can apply

    De-Broglie equation, to obtain the velocity.

    \lambda=\frac{h}{mv}\\v=\frac{6.626\times10^{-34}Js}{84kg\times1m}\\v=7.89\times10^{-36}m/s

    The velocity of the person is 7.89\times10^{-36}m/s

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