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## The current through a wire that is 0.80 m long is 5.0 A. The wire is at right angles to a 0.60 T magnetic field. What is the magnitude of th

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## Answers ( )

Answer: B

F = 2.4 N

Explanation: Given that

Magnetic field B = 0.60 T

Current I = 5 A

Length L = 0.8 m

The force on an individual charge moving at the drift velocity Vd is given by F = qVdB sin θ.

Since current = charge/time

I = q/t

q = It

Also, recall that V = L/t. Therefore

F = I × t × L/t × B × sinØ

F = ILBsin θ

Since the wire is at right angles to the magnetic field

Sin θ = sin 90 = 1 then,

F = 5 × 0.8 × 0.6 = 2.4N

The force on the wire is 2.4 N