The current through a wire that is 0.80 m long is 5.0 A. The wire is at right angles to a 0.60 T magnetic field. What is the magnitude of th

Question

The current through a wire that is 0.80 m long is 5.0 A. The wire is at right angles to a 0.60 T magnetic field. What is the magnitude of the force on the wire?

0.24 N

2.4 N

24 N

240 N

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Kim Chi 3 years 2021-07-16T00:37:10+00:00 1 Answers 15 views 0

Answers ( )

  1. Doris
    0
    2021-07-16T00:38:19+00:00
    Reply

    Answer: B

    F = 2.4 N

    Explanation: Given that

    Magnetic field B = 0.60 T

    Current I = 5 A

    Length L = 0.8 m

    The force on an individual charge moving at the drift velocity Vd is given by F = qVdB sin θ.

    Since current = charge/time

    I = q/t

    q = It

    Also, recall that V = L/t. Therefore

    F = I × t × L/t × B × sinØ

    F = ILBsin θ

    Since the wire is at right angles to the magnetic field

    Sin θ = sin 90 = 1 then,

    F = 5 × 0.8 × 0.6 = 2.4N

    The force on the wire is 2.4 N

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