The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in the anion?

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The coordination compound Co3[Cr(CN)6]2 contains Co2+ cations and a complex anion. What is the likely oxidation state for Cr in the anion?

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3 years 2021-07-29T17:20:37+00:00 1 Answers 33 views 0

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    2021-07-29T17:22:00+00:00

    Answer:

    -3

    Explanation:

    The oxidation state or oxidation number of an atom is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

    The complex anion here is [Cr(CN)6]3-.

    Now, as the oxidation state of CN or cyanide ligand is -1, and if we suppose the oxidation state of Cr to be ‘x’, then; x – 6 = -3 (overall charge on the anion),

    so x= +3. Hence the oxidation state of Chromium in this complex hexacyanochromium (III) anion comes out to be -3.

    .

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )