the 10th term of the arithmetic 5x + 6, 11x + 2, 17x – 2,

Question

the 10th term of the arithmetic 5x + 6, 11x + 2, 17x – 2,

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Xavia 3 years 2021-07-25T12:22:29+00:00 1 Answers 9 views 0

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    2021-07-25T12:24:09+00:00

    Answer:

    t10 = 59x – 30

    Step-by-step explanation:

    a = 5x + 6

    d = 11x + 2 – 5x – 6

    d = 6x – 4

    n = 10

    tn = a + (n – 1)*d

    t10 = 5x + 6 + (10 – 1) ( 6x – 4)

    t10 = 5x + 6 + 9(6x – 4)

    t10 = 5x + 6 + 54x – 36

    t10 = 59x – 30

    Check by finding the 3rd term

    d = 6x – 4

    n = 3

    a = 5x + 6

    t3 = 5x + 6 + (3-1)*(6x – 4)

    t3 = 5x + 6 + 2(6x – 4)

    t3 = 5x + 6 + 12x – 8

    t3 = 17x – 2 which is exactly what it should be.

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