ten times the smallest of three consecutive integers is twenty two more than three times the sum of the integers. find the integers​

Question

ten times the smallest of three consecutive integers is twenty two more than three times the sum of the integers. find the integers​

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Phúc Điền 5 years 2021-08-28T15:43:28+00:00 1 Answers 48 views 0

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  1. Calantha
    0
    2021-08-28T15:44:35+00:00
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    Answer:

    31, 32 and 33

    Step-by-step explanation:

    Mark these consecutive integers as (n-1), n and (n+1)

    (n-1) is the smallest of them

    Now write the equation

    10 * (n-1) = 3 * (n-1 + n + n+1) + 22

    10n – 10 = 3 * (n + n + n) + 22

    10n – 10 = 3 * 3n + 22

    10n – 10 = 9n + 22

    10n – 9n = 22 + 10

    n = 32

    Now find these three integers

    n-1 = 32 – 1 = 31

    n = 32

    n+1 =32 + 1 =33

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