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Answers ( )
I suppose you just have to simplify this expression.
(2ˣ⁺² – 2ˣ⁺³) / (2ˣ⁺¹ – 2ˣ⁺²)
Divide through every term by the lowest power of 2, which would be x + 1 :
… = (2ˣ⁺²/2ˣ⁺¹ – 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ – 2ˣ⁺²/2ˣ⁺¹)
Recall that nª / nᵇ = nª⁻ᵇ, so that we have
… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ – 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ – 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)
… = (2¹ – 2²) / (2⁰ – 2¹)
… = (2 – 4) / (1 – 2)
… = (-2) / (-1)
… = 2
Another way to get the same result: rewrite every term as a multiple of y = 2ˣ :
… = (2²×2ˣ – 2³×2ˣ) / (2×2ˣ – 2²×2ˣ)
… = (4×2ˣ – 8×2ˣ) / (2×2ˣ – 4×2ˣ)
… = (4y – 8y) / (2y – 4y)
… = (-4y) / (-2y)
… = 2