tan^2 A – sin^2 A = tan^2 A.sin^2 A ​

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tan^2 A – sin^2 A = tan^2 A.sin^2 A

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Helga 3 years 2021-09-03T18:32:02+00:00 1 Answers 0 views 0

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    2021-09-03T18:33:42+00:00

    Answer:

    step by step calculation :

    To proof:

    tan²A – sin²A = tan² A sin²A

    from LHS,

    tan²A -sin²A

    = (sin²A / cos²A) – sin²A……[tan A=sin A/cos A]

    = (sin²A – sin²Acos²A) / cos²A

    = sin²A (1- cos²A) / cos² A [tan A = sinA / cos A]

    = tan²A sin²A= RHS

    .•. hence proved

    hope it helped:)

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