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tan^2 A – sin^2 A = tan^2 A.sin^2 A
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tan^2 A – sin^2 A = tan^2 A.sin^2 A
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Mathematics
3 years
2021-09-03T18:32:02+00:00
2021-09-03T18:32:02+00:00 1 Answers
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Answer:
step by step calculation :
To proof:
tan²A – sin²A = tan² A sin²A
from LHS,
tan²A -sin²A
= (sin²A / cos²A) – sin²A……[tan A=sin A/cos A]
= (sin²A – sin²Acos²A) / cos²A
= sin²A (1- cos²A) / cos² A [tan A = sinA / cos A]
= tan²A sin²A= RHS
.•. hence proved
hope it helped:)