Suppose we have an infinitely long wire that is smoothed out into a quarter arc. In other words, the wire runs from y = +[infinity] to the p

Question

Suppose we have an infinitely long wire that is smoothed out into a quarter arc. In other words, the wire runs from y = +[infinity] to the point (0, b), then joined by a circular arc with radius b (centered at the point P(b, b)), continue on from (b, 0) to x = +[infinity], with b = 0.76 m. What is the magnitude of the magnetic field B (in T) at the point P(b, b) if the current is 2.9 A?

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Nick 3 years 2021-08-16T04:10:47+00:00 1 Answers 3 views 0

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  1. ThanhThu
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    2021-08-16T04:12:14+00:00
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    Answer:

    The magnetic field B is 1.34×10^-5 T

    Explanation:

    The semi-infinite current along the y axis and in the magnetic field is equal to:

    B1=((uo*I)/2)/(2*π*b)

    the semi-infinite current along the x axis is equal to:

    B2=((uo*I)/2)/(2*π*b)

    the quart circle current is equal to:

    B3=((uo*I)/4)/(2*π*b)

    Btotal=B1+B2+B3

    replacing:

    Btotal=((uo*I)/2)/(2*π*b) + ((uo*I)/2)/(2*π*b) + ((uo*I)/4)/(2*π*b)

    Btotal=((uo*I)/b)*((1/(4*π))+(1/(4*π))+(1/8))

    Btotal=((4*π*10^-7*2.9)/0.76)*(0.28)=1.34×10^-5 T

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