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Suppose the counter attendant pushes a 0.27 kgkg bottle with the same initial speed on a different countertop and it travels 1.7 mm before s
Question
Suppose the counter attendant pushes a 0.27 kgkg bottle with the same initial speed on a different countertop and it travels 1.7 mm before stopping. What is the magnitude of the friction force from this second counter
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Physics
3 years
2021-08-18T15:46:24+00:00
2021-08-18T15:46:24+00:00 1 Answers
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Answer:
The force of friction is 622.58 N.
Explanation:
Given that,
Mass of the bottle, m = 0.27 kg
Finally it stops, v = 0
Distance traveled by the bottle, d = 1.7 mm = 0.0017 m
Let the initial speed of the bottle, u = 2.8 m/s
Let f is the force of friction is acting on the bottle. The force of friction is given by Newton’s second law of motion as :
Using third equation of motion :
f = -622.58 N
So, the force of friction is 622.58 N.