Suppose that a box is accelerating at a rate of 4 m/s2. If the net force is tripled and the mass is doubled, then what is the new accelerati

Question

Suppose that a box is accelerating at a rate of 4 m/s2. If the net force is tripled and the mass is doubled, then what is the new acceleration of the box?

in progress 0
Gia Bảo 3 years 2021-09-05T10:54:33+00:00 2 Answers 5 views 0

Answers ( )

  1. Answer: 6m/s2

    Explanation: Recall, F =ma

    a =F/m

    Where a = 4m/s2

    So, 4 =F/m ………….. equation ( 1)

    Now we shall see the value of a where 3F and 2m

    Thus,

    a =F/m

    a = 3F/2m

    a =3/2 ×F/m …………… equation ( 2 )

    Now, substitute equation 1 into 2

    F/m = 4

    a =3/2 ×4

    a = 12/2

    a = 6m/s2

    0
    2021-09-05T10:55:51+00:00

    Answer:

    The new acceleration of the box = 6 m/s²

    That is, 1.5 of the old acceleration.

    Explanation:

    Acceleration of the box = 4 m/s²

    From Newton’s law, F = ma

    F = 4m (eqn 1)

    Then the force is tripled, that is, New force, F₁ = 3F

    the mass is doubled, New mass, m₁ = 2m

    This will produce new acceleration, a₁

    Still consistent with Newton’s law

    New force = New mass × New acceleration

    F₁ = m₁ × a₁

    3F = 2m × a₁

    a₁ = 3F/(2m)

    But from eqn 1

    F = 4m

    a₁ = 3(4m)/2m = 3×4/2 = 6 m/s²

    Hence the new acceleration = 6 m/s²

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )