Suppose a clay model of a koala bear has a mass of 0.250 kg and slides on ice at a speed of 0.700 m/s. It runs into another clay model, whic

Question

Suppose a clay model of a koala bear has a mass of 0.250 kg and slides on ice at a speed of 0.700 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.325 kg. Both being soft clay, they naturally stick together. What is their final velocity (in m/s)

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MichaelMet 5 years 2021-08-29T05:05:01+00:00 1 Answers 86 views 0

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  1. mit
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    2021-08-29T05:06:11+00:00
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    Answer:

    The final velocity of the system is 0.304 m/s.

    Explanation:

    Given that,

    Mass of the 1 clay model, m_1=0.25\ kg

    Mass of the second clay model, m_2=0.325\ kg

    Initial speed of the first clay model, u_1=0.7\ m/s

    Initial speed of the second clay model, u_2=0 (at rest)

    Both being soft clay, they naturally stick together. It is a case of inelastic collision. The momentum of the system remains conserved such that :

    m_1u_1+m_2u_2=(m_1+m_2)V

    V is the final velocity of the system

    V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{0.25\times 0.7}{(0.25+0.325)}\\\\V=0.304\ m/s

    So, the final velocity of the system is 0.304 m/s. Hence, this is the required solution.

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