Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat =

Question

Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat = 0.4494 J/g·°C) at 0.00°C, and the two blocks are insulated from the rest of the universe. The final temperature of the two blocks will be:

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RuslanHeatt 5 years 2021-08-12T03:15:35+00:00 1 Answers 376 views 0

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  1. thuhuong
    0
    2021-08-12T03:17:22+00:00
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    Answer:

    34.34 °C

    Explanation:

    From the question,

    Heat lost by the silver block = heat gained by the iron block.

    cm(x-y) = c’m'(y-z)………………. Equation 1

    Where c = specific heat capacity of the silver block, m = mass of the silver block, c’ = specific heat capacity of the iron, m’ = mass of the iron. x = initial temperature of the silver block, z = initial temperature of the iron,  y = final temperature of the mixture.

    make y the subject of the equation

    y = (cmx+c’m’z)/(cm+c’m’)…………… Equation 2

    Given: c = 50 g, c = 0.2350 J/g·°C, x = 100°C, m’ = 50 g, c’ = 0.4494 J/g.°C, z = 0°C

    Substitute these values into equation 2

    y = [(50×0.2350×100)+(50×0.4494×0)]/[(50×0.2350)+(50+0.4494)]

    y = 1175/(11.75+22.47)

    y = 1175/34.22

    y = 34.34 °C

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