$\sqrt[]{x^2+48}$ = 4x-3 +$\sqrt[]{x^2+35}$ Question $\sqrt[]{x^2+48}$ = 4x-3 +$\sqrt[]{x^2+35}$ 0 Môn Toán Tryphena 4 years 2020-11-18T00:16:09+00:00 2020-11-18T00:16:09+00:00 0 Answers 40 views 0
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