# Solve the quadratic equation 27y^2-314y+699​

Question

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1 year 2021-09-04T17:51:50+00:00 1 Answers 9 views 0

$$3; \frac{233}{27}$$.

Step-by-step explanation:

1) to calculate the discriminant of the given equation:

D=(314/2)²-699*27=5776.

2) to calculate the roots of the given equation:

$$\left[\begin{array}{ccc}y=\frac{157-\sqrt{5776} }{27} \\ y=\frac{157+\sqrt{5776} }{27} \end{array}$$

$$<=> \ \left[\begin{array}{ccc}y=3\\y=\frac{233}{27} \end{array}$$