solve the equation (x-3)^3-( x – 1 )^3 + 7x^2 = 7(3x – 4 )

Question

solve the equation
(x-3)^3-( x – 1 )^3 + 7x^2 = 7(3x – 4 )

in progress 0
Sapo 4 years 2021-09-04T05:28:16+00:00 1 Answers 4 views 0

Answers ( )

  1. lethu
    0
    2021-09-04T05:29:28+00:00
    Reply

    Answer:

    x= -1 or x = -2

    Step-by-step explanation:

    Your equation:

    (x−3)^3−(x−1)^3+7x^2=7(3x−4)

    Step 1: Simplify both sides of the equation.

    x^2+24x−26=21x−28

    Step 2: Subtract 21x-28 from both sides.

    x^2+24x−26−(21x−28)=21x−28−(21x−28)

    x^2+3x+2=0

    Step 3: Factor left side of equation.

    (x+1)(x+2)=0

    Step 4: Set factors equal to zero.

    x+1=0 or x+2=0

    which equals to x=−1 or x=−2

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )