Solve for x \frac{x}{2}+\frac{x}{7}=−1

Question

Solve for x
\frac{x}{2}+\frac{x}{7}=−1

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Bình An 5 years 2021-08-31T06:14:21+00:00 2 Answers 12 views 0

Answers ( )

  1. linhdan
    0
    2021-08-31T06:15:32+00:00
    Reply

    \Large \underline{\tt Given} :

    • \tt \dfrac{x}{2}+\dfrac{x}{7} = - 1

    \\

    \Large \underline{\tt To \: Find} :

    • Value of x = ?

    \\

    \Large \underline{\tt Solution} :

    \tt \dashrightarrow \dfrac{x}{2}+\dfrac{x}{7} = - 1

    \tt \dashrightarrow \dfrac{7x + 2x}{2\times 7}= - 1

    \tt \dashrightarrow \dfrac{9x}{14}= - 1

    \tt \dashrightarrow 9x= - 1\times 14

    \tt \dashrightarrow 9x= - 14

    \tt \dashrightarrow x= - \dfrac{14}{9}

    \\

    \bf Hence, \:value\: of \: x = - \dfrac{14}{9}

  2. Adela
    0
    2021-08-31T06:15:52+00:00
    Reply

    Answer:

    x = -\frac{14}{9}  

    I hope this helps!

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )