Solve for d small diameter A=\frac{\pi *D^{2} }{4} - \frac{\pi *d^{2} }{4}

Question

Solve for d small diameter
A=\frac{\pi *D^{2} }{4} - \frac{\pi *d^{2} }{4}

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Trúc Chi 5 years 2021-09-04T14:50:34+00:00 2 Answers 26 views 0

Answers ( )

  1. RuslanHeatt
    0
    2021-09-04T14:51:48+00:00
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    Answer:

    \boxed{ \tt{d = \sqrt{D^{2} -\frac{4A}{\pi}} }}

    Step-by-step explanation:

    if \: A=\frac{\pi *D^{2} }{4} - \frac{\pi *d^{2} }{4} \\ then \to \\ A = \frac{\pi}{4} (D^{2} - {d}^{2} ) \\ (D^{2} - {d}^{2} ) \pi = 4A \\ D^{2} - {d}^{2} = \frac{4A}{\pi} \\ {d}^{2} = D^{2} -\frac{4A}{\pi} \\ d = \sqrt{D^{2} -\frac{4A}{\pi}}

  2. giabao
    0
    2021-09-04T14:51:54+00:00
    Reply

    Answer:

    \boxed{\text{\Large \sqrt{-1.27324A+D^2}$}}

    Step-by-step explanation:

    \displaystyle A=\frac{\pi \times D^2}{4} - \frac{\pi \times d^2}{4}

    \displaystyle A=0.785398D^2 - 0.785398d^2

    Solve for d

    \displaystyle A-0.785398D^2= - 0.785398d^2

    \displaystyle \frac{A-0.785398D^2}{- 0.785398} = d^2

    -1.27324A+D^2=d^2

    \displaystyle \sqrt{-1.27324A+D^2} =d

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