Simplify: 4(r + 1) + 3r A. 4r + 4 B. 5r + 1 C. 7r + 1 D. 7r + 4

Question

Simplify:

4(r + 1) + 3r

A. 4r + 4
B. 5r + 1
C. 7r + 1
D. 7r + 4

in progress 0
Khang Minh 4 years 2021-09-01T01:16:18+00:00 2 Answers 11 views 0

Answers ( )

  1. thanhha
    0
    2021-09-01T01:18:04+00:00
    Reply

    Answer:

    look in the explanation, it is in there

    Step-by-step explanation:

    i don’t know if you are distributing or just using PEMDAS .

    if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r

                            7r +4

                          is what i got!

    If you are doing PEMDAS then: first you do what is inside the perenthisis ()

    4(r + 1) +3r changes into

    4( r1 ) + 3r now you do multipulcation because that in the “M” in pemdas

    4r + 3r, then if you are using like terms you would add them

    7r

    i hope this helps you out!

  2. Nho
    0
    2021-09-01T01:18:09+00:00
    Reply

    the correct answer is , D. 7r + 4
    using the pemdas method will result in the correct answer .

    1. distribute 4 to r and 1
    •4r and 4 (4r + 4)
    2. combine like terms
    •4r and 3r (4r+3r)
    3. add like terms together
    •4r + 3r = 7r
    4. since our constant from step one has no other like terms , it stays as is resulting in our answer being : D. 7r + 4

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