the correct answer is , D. 7r + 4 using the pemdas method will result in the correct answer .
1. distribute 4 to r and 1 •4r and 4 (4r + 4) 2. combine like terms •4r and 3r (4r+3r) 3. add like terms together •4r + 3r = 7r 4. since our constant from step one has no other like terms , it stays as is resulting in our answer being : D. 7r + 4
Answer:
look in the explanation, it is in there
Step-by-step explanation:
i don’t know if you are distributing or just using PEMDAS .
if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r
7r +4
is what i got!
If you are doing PEMDAS then: first you do what is inside the perenthisis ()
4(r + 1) +3r changes into
4( r1 ) + 3r now you do multipulcation because that in the “M” in pemdas
4r + 3r, then if you are using like terms you would add them
7r
i hope this helps you out!
the correct answer is , D. 7r + 4
using the pemdas method will result in the correct answer .
1. distribute 4 to r and 1
•4r and 4 (4r + 4)
2. combine like terms
•4r and 3r (4r+3r)
3. add like terms together
•4r + 3r = 7r
4. since our constant from step one has no other like terms , it stays as is resulting in our answer being : D. 7r + 4