4(r + 1) + 3r
A. 4r + 4 B. 5r + 1 C. 7r + 1 D. 7r + 4
look in the explanation, it is in there
i don’t know if you are distributing or just using PEMDAS .
if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r
is what i got!
If you are doing PEMDAS then: first you do what is inside the perenthisis ()
4(r + 1) +3r changes into
4( r1 ) + 3r now you do multipulcation because that in the “M” in pemdas
4r + 3r, then if you are using like terms you would add them
i hope this helps you out!
the correct answer is , D. 7r + 4 using the pemdas method will result in the correct answer .
1. distribute 4 to r and 1 •4r and 4 (4r + 4)2. combine like terms •4r and 3r (4r+3r)3. add like terms together •4r + 3r = 7r4. since our constant from step one has no other like terms , it stays as is resulting in our answer being : D. 7r + 4
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