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SHOW YOUR SOLUTION set is a driver providing a professional motorcycle ride to commuters he has a base care of php 50 for the first 2 k
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SHOW YOUR SOLUTION
set is a driver providing a professional motorcycle ride to commuters he has a base care of php 50 for the first 2 km travelled php 10 for every kilometer thereafter.
Questions:
1.write the line equation expressing the fare paid (y) in relation of the distance (x) covered by a motorcycle.
2.How much will seth receive if they travel 5 km?
3.About how many kilometers can a passenger travel if he she has php 120?
4.using your answer in number one will write the equation of the line in the form Ax + By = C.
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Mathematics
3 years
2021-07-28T06:01:06+00:00
2021-07-28T06:01:06+00:00 1 Answers
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Answers ( )
We are given:
The base care + first 2 km price = 50 php
Cost for every subsequent km = 10 php
Solving the questions:
Question 1:
We are given that the driver will charge 50 php for the first 2 km
and then will charge 10 php for every km after that
In the equation, (y) has to be the fare paid and (x) is the distance travelled
So, our fare (y) will be 50 php the second we sit on the bike, and after the first 2 km, we will be charged 10php/km
It can be written as:
y = 50 + 10(x-2)
I multiplied 10 by x-2 since the price of 10 php/km starts after we have travelled 2 km
Question 2:
Since we now have our equation, we are asked the cost if We travel 5 km
y = 50 + 10(x-2)
We know that in this equation, x is the distance travelled and y is the fare
Since we are told that the distance covered is 5 km:
y = 50 + 10(5-2)
y = 50 + 30
y = 80 php
Question 3:
We are asked the distance travelled if we have 120 php
We know that in the equation, y is the fare paid and x is the distance travelled
Since we are told that the fare paid is 120 php:
y = 50 + 10(x-2)
120 = 50 + 10(x-2)
120 – 50 = 10x – 20
10x = 90
x = 9 km
Question 4:
Rewriting our equation in the form, Ax + By = C
We have the equation:
y = 50 + 10(x-2)
y = 50 + 10x – 20
y = 30 + 10x
0 = 30 + 10x – y [subtracting y from both sides]
10x – y = -30 [subtracting 30 from both sides]