Se requiere mover un bloque cuyo peso tiene una magnitud de 30N sobre una superficie Horizontal a una velocidad constante,si el coeficiente

Question

Se requiere mover un bloque cuyo peso tiene una magnitud de 30N sobre una superficie Horizontal a una velocidad constante,si el coeficiente de fricción dinámico es de 0.5, determine la magnitud de aceleración que adquirirá el bloque si se le aplica el doble de la magnitud de la fuerza calculada.

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Sigridomena 5 years 2021-09-04T15:25:31+00:00 1 Answers 185 views 0

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  1. thanhha
    1
    2021-09-04T15:26:48+00:00
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    Answer:

    We need to apply a force of 15 Netwons in order to move the block at a constant velocity.

    For the second context the acceleration is 4.90 meters per square second.

    Explanation:

    Notice that the problem is about a block, which we need to move with constant velocity, that means there’s no acceleration, because the velocity doesn’t variate.

    We use Newton’s Second Law \Sigma F = ma

    Where \Sigma W=mg= 30 \N and \mu = 0.5 (friction coefficient).

    In this case, we know that \Sigma F=0, because there’s no acceleration.

    F - f_{\mu}=0

    Where, f_{\mu} = \mu N = \mu W = 0.5(30)=15 \ N

    Therefore, F= 15 \ N, which means we need to apply a force of 15 Netwons in order to move the block at a constant velocity.

    Now, in case we use double force F= 30 \ N, we need to find the mass of the block using g= 9.81 \ m/s^{2}

    mg=30\\m=\frac{30}{9.81} \approx 3.06 \ kg

    Now, according to Newton’s Second Law, we have

    F - f_{\mu}=ma\\

    Replacing all values and solving for a, we have

    30-15=3.06a\\a=\frac{15}{3.06} \approx 4.90 \ m/s^{2}

    Therefore, for the second context the acceleration is 4.90 meters per square second.

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