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Radar consists of electromagnetic waves. A warplane is rendered invisible to enemy radar by applying an antireflective polymer coating. If r
Question
Radar consists of electromagnetic waves. A warplane is rendered invisible to enemy radar by applying an antireflective polymer coating. If radar waves have a frequency of 10 GHz (Giga = 1E9), and the index of refraction of the polymer for these waves is 1.50, what is the minimum thickness of the antireflective coating? (c = 3E8 m/s. The index of refraction of air is ~1, and that of the fuselage is larger than for the polymer coating)
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4 years
2021-09-04T05:29:30+00:00
2021-09-04T05:29:30+00:00 1 Answers
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Answer:
d = 0.015m
Explanation:
To find the thickness of the antireflective coating you take into account that waves must reflect and interfere destructively between them. A wave travels twice the thickness d of the coating, and for the destructive interference it is necessary that the reflected wave is (m+1/2) factor of the incident wave. Thus, you have:
d: thickness of the coating
m: order of the interference (m=1 for the minimum thickness)
λn: wavelength of light inside the coating
You first calculate the wavelength of the wave:
Then, you replace the values of m and λn in order to calculate d:
hence, the thickness of the antireflective coating must be 0.015m