ptsA flashlight is pointed at the ground, forming a spot of light. The radius of the spot of light is measured and the area of the spot is c

Question

ptsA flashlight is pointed at the ground, forming a spot of light. The radius of the spot of light is measured and the area of the spot is calculated. The brightness of the spot is measured. Then the flashlight is moved so it is twice as far from the floor.The new brightness will be ________ times the old brightness.

in progress 0
Thiên Hương 4 years 2021-07-17T11:31:53+00:00 1 Answers 7 views 0

Answers ( )

  1. Neala
    0
    2021-07-17T11:32:54+00:00
    Reply

    Answer:

    I₂ = I₀  1/4

    Explanation:

    For this exercise we use the definition of intensity which is the power per unit area

             I = P / A

    The emitted power is constant, so

         P = I A

    We can write this equation for the start and end point with index 2

        I₀ A₀ = I₂ A₂

        I₂ = I₀ A₀ / A₂

    The spot area is the area of ​​the circle

          A₀ = π r₀²

    We substitute

         I₂ = I₀ r₀² / r₂²

    It indicates that the radius of the spot is twice the initial radius

          r₂ = 2 r₀

          I₂ = I₀ (r₀ / 2 r₀)²

          I₂ = I₀  1/4

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )