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## ) (Problem 2.35 from text) Consider a light wave having a phase velocity of 3×10-8 m/s and a frequency of 6×1014 Hz. What is the shortest di

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) (Problem 2.35 from text) Consider a light wave having a phase velocity of 3×10-8 m/s and a frequency of 6×1014 Hz. What is the shortest distance along the wave between any two points that have a phase difference of 300

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Physics
3 years
2021-08-24T21:52:45+00:00
2021-08-24T21:52:45+00:00 1 Answers
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## Answers ( )

Answer:The shortest distance covered by the wave between the given points is.Explanation:The

Phase velocity() of any wave can be written aswhere ‘‘ is the angular velocity and ‘‘ is the wave number.

Also, if ‘‘ is the frequency of the wave, then

Given, , and the phase difference between two points is .

If the wave travels by the shortest distance of between these points, then we can write

[tex]\v_{p} = \dfrac{\omega}{k}[/tex]