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) (Problem 2.35 from text) Consider a light wave having a phase velocity of 3×10-8 m/s and a frequency of 6×1014 Hz. What is the shortest di
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) (Problem 2.35 from text) Consider a light wave having a phase velocity of 3×10-8 m/s and a frequency of 6×1014 Hz. What is the shortest distance along the wave between any two points that have a phase difference of 300
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2021-08-24T21:52:45+00:00
2021-08-24T21:52:45+00:00 1 Answers
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Answer:
The shortest distance covered by the wave between the given points is
.
Explanation:
The Phase velocity (
) of any wave can be written as
where ‘
‘ is the angular velocity and ‘
‘ is the wave number.
Also, if ‘
‘ is the frequency of the wave, then
Given,
,
and the phase difference between two points is
.
If the wave travels by the shortest distance of
between these points, then we can write