## Polygon A is similar to polygon B the sides of polygon A are three times larger then the corresponding sides of polygon B the perimeter of p

Question

Polygon A is similar to polygon B the sides of polygon A are three times larger then the corresponding sides of polygon B the perimeter of polygon A is 144 what is the perimeter of polygon B ?

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3 years 2021-08-08T13:09:12+00:00 2 Answers 11 views 0

• 48 units

Step-by-step explanation:

Perimeter is the sum of the side lengths

If polygon A has perimeter

• P  = a+b+c+d for example

Then polygon B has perimeter of

• P’ = 1/3a+1/3b+1/3+1/3d = 1/3P as each side is 3 times smaller than the corresponding side

Since P = 144

• P’ = 1/3P = 1/3*144 = 48 units
2. We can write a ratio comparing the sides of both polygons.

A:B = 3:1

Since we know that 144 is the perimeter for polygon A, we can substitute it.

144:B = 3:1

~Simplify

144 = 3B

Divide 3 to both sides

48 = B

Therefore, the perimeter of B is 48 units.

Best of Luck!